Male pattern baldness is a recessive sex-linked trait on the X chromosome Xb A woman whose father had male marries man with this What probability that any son boor?

Let's represent:

- Xb: recessive allele for male pattern baldness

- X: dominant allele for normal hair growth

Given:

- The woman's father had male pattern baldness (XbY)

- The woman (carrier) has one copy of the recessive allele (XbX)

- The man has normal hair growth (XY)

The woman's genotype: XbX

The man's genotype: XY

When a carrier mother (XbX) mates with a man with normal hair growth (XY), the possible genotypes for their male offspring (sons) are:

1. XbY: Son with male pattern baldness (50% probability)

2. XY: Son with normal hair growth (50% probability)

In this case, there is a 50% probability that any son born to this couple will have male pattern baldness.